1955 Ford F vs. 1998 Mazda Sentia

To start off, 1998 Mazda Sentia is newer by 43 year(s). Which means there will be less support and parts availability for 1955 Ford F. In addition, the cost of maintenance, including insurance, on 1955 Ford F would be higher. At 4,458 cc (8 cylinders), 1955 Ford F is equipped with a bigger engine. In terms of performance, 1998 Mazda Sentia (159 HP @ 5500 RPM) has 3 more horse power than 1955 Ford F. (156 HP @ 3000 RPM) In normal driving conditions, 1998 Mazda Sentia should accelerate faster than 1955 Ford F. With that said, vehicle weight also plays an important factor in acceleration. 1955 Ford F weights approximately 480 kg more than 1998 Mazda Sentia.

Both vehicles are rear wheel drive (RWD) - it offers better handling in dry conditions; in addition, if you are looking to drift, both vehicles do the job better than front wheel drive vehicles. With that said, do keep in mind that many other factors such as speed and the wear on your tires can also have significant impact on traction and control. 1998 Mazda Sentia has automatic transmission and 1955 Ford F has manual transmission. 1955 Ford F will offer better control over acceleration and deceleration in addition to better fuel efficiency overall. 1998 Mazda Sentia will be easier to drive especially in heavy traffic.

Compare all specifications:

1955 Ford F 1998 Mazda Sentia
Make Ford Mazda
Model F Sentia
Year Released 1955 1998
Body Type Pickup Sedan
Engine Position Front Front
Engine Size 4458 cc 2954 cc
Engine Cylinders 8 cylinders 6 cylinders
Engine Type V in-line
Horse Power 156 HP 159 HP
Engine RPM 3000 RPM 5500 RPM
Fuel Type Gasoline Gasoline
Drive Type Rear Rear
Transmission Type Manual Automatic
Number of Seats 5 seats 5 seats
Vehicle Weight 2040 kg 1560 kg
Vehicle Width 1880 mm 1800 mm
Wheelbase Size 3000 mm 2860 mm