1998 Ford F-150 vs. 2008 Porsche 911

To start off, 2008 Porsche 911 is newer by 10 year(s). Which means there will be less support and parts availability for 1998 Ford F-150. In addition, the cost of maintenance, including insurance, on 1998 Ford F-150 would be higher. At 4,195 cc (6 cylinders), 1998 Ford F-150 is equipped with a bigger engine. In terms of performance, 2008 Porsche 911 (405 HP @ 3500 RPM) has 202 more horse power than 1998 Ford F-150. (203 HP @ 4750 RPM) In normal driving conditions, 2008 Porsche 911 should accelerate faster than 1998 Ford F-150. With that said, vehicle weight also plays an important factor in acceleration. 1998 Ford F-150 weights approximately 635 kg more than 2008 Porsche 911.

Because 1998 Ford F-150 is four wheel drive (4WD), it will have significant more traction and grip than 2008 Porsche 911. In wet, icy, snow, or gravel driving conditions, 1998 Ford F-150 will offer significantly more control. With that said, do keep in mind that many other factors such as speed and the wear on your tires can also have significant impact on traction and control. Let's talk about torque, 2008 Porsche 911 (620 Nm @ 3500 RPM) has 282 more torque (in Nm) than 1998 Ford F-150. (338 Nm @ 3000 RPM). This means 2008 Porsche 911 will have an easier job in driving up hills or pulling heavy equipment than 1998 Ford F-150.

Compare all specifications:

1998 Ford F-150 2008 Porsche 911
Make Ford Porsche
Model F-150 911
Year Released 1998 2008
Body Type Pickup Coupe
Engine Position Front Rear
Engine Size 4195 cc 3600 cc
Engine Cylinders 6 cylinders 6 cylinders
Engine Type in-line boxer
Horse Power 203 HP 405 HP
Engine RPM 4750 RPM 3500 RPM
Torque 338 Nm 620 Nm
Torque RPM 3000 RPM 3500 RPM
Fuel Type Gasoline Gasoline
Drive Type 4WD Rear
Transmission Type Manual Manual
Number of Seats 2 seats 2 seats
Vehicle Weight 2075 kg 1440 kg
Vehicle Length 5230 mm 4790 mm
Vehicle Height 1850 mm 1710 mm
Wheelbase Size 3050 mm 2360 mm