1999 Dodge Dakota vs. 2008 Ford F-450
To start off, 2008 Ford F-450 is newer by 9 year(s). Which means there will be less support and parts availability for 1999 Dodge Dakota. In addition, the cost of maintenance, including insurance, on 1999 Dodge Dakota would be higher. At 6,400 cc (8 cylinders), 2008 Ford F-450 is equipped with a bigger engine. In terms of performance, 2008 Ford F-450 (350 HP @ 3000 RPM) has 232 more horse power than 1999 Dodge Dakota. (118 HP @ 5200 RPM) In normal driving conditions, 2008 Ford F-450 should accelerate faster than 1999 Dodge Dakota.
Because 1999 Dodge Dakota is four wheel drive (4WD), it will have significant more traction and grip than 2008 Ford F-450. In wet, icy, snow, or gravel driving conditions, 1999 Dodge Dakota will offer significantly more control. With that said, do keep in mind that many other factors such as speed and the wear on your tires can also have significant impact on traction and control. Let's talk about torque, 2008 Ford F-450 (881 Nm @ 2000 RPM) has 685 more torque (in Nm) than 1999 Dodge Dakota. (196 Nm @ 3250 RPM). This means 2008 Ford F-450 will have an easier job in driving up hills or pulling heavy equipment than 1999 Dodge Dakota.
Compare all specifications:
1999 Dodge Dakota | 2008 Ford F-450 | |
Make | Dodge | Ford |
Model | Dakota | F-450 |
Year Released | 1999 | 2008 |
Body Type | Pickup | Pickup |
Engine Position | Front | Front |
Engine Size | 2456 cc | 6400 cc |
Engine Cylinders | 4 cylinders | 8 cylinders |
Engine Type | in-line | V |
Horse Power | 118 HP | 350 HP |
Engine RPM | 5200 RPM | 3000 RPM |
Torque | 196 Nm | 881 Nm |
Torque RPM | 3250 RPM | 2000 RPM |
Fuel Type | Gasoline | Diesel |
Drive Type | 4WD | Rear |
Transmission Type | Manual | Manual |
Number of Seats | 3 seats | 6 seats |
Vehicle Length | 4980 mm | 6670 mm |
Vehicle Width | 1820 mm | 2430 mm |
Vehicle Height | 1670 mm | 2030 mm |
Wheelbase Size | 2850 mm | 4390 mm |